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6m^2-6m+5m-14=0
We add all the numbers together, and all the variables
6m^2-1m-14=0
a = 6; b = -1; c = -14;
Δ = b2-4ac
Δ = -12-4·6·(-14)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{337}}{2*6}=\frac{1-\sqrt{337}}{12} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{337}}{2*6}=\frac{1+\sqrt{337}}{12} $
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